REMOVABLE AND NONREMOVABLE DISCONTINUITY
CONTINUITY
IF Lim f(x)= Lim f(x) = f(a)
x->a- x->a+
THEN
FUNCTION IS CONTINUOUS AT 'a'
WHERE , Lim f(x) is a left hand limit
x->a-
Lim f(x) is a right hand limit
x->a+
REMOVABLE DISCONTINUITY
IF Left hand limit = Right hand limit
But f(a) is different; then it is called as Removable Discontinuity
So; Lim f(x)= Lim f(x) but not equal to f(a)
x->a - x->a+
Then f(x) has removable discontinuity
WE CAN REMOVE THIS DISCONTINUITY BY DEFINING
VALUE OF F(a)
EX:
1. Let f(x)= 2x.x , for 1≤ x<3
= 20 , for x=3
=6x , for 3<x≤5
This is example of removable discontinuity
because;
Lim f(x)=2x.x=2.3.3=18
x->3-
Lim f(x)=6x=6.3=18
x->3+
But f(3)=20
so; left hand limit and right hand limits are same(18)
but f(3) is different (20).
Hence function is not continuous at 3.
IF WE DEFINE F(3)=18; LEFT HAND LIMIT , RIGHT HAND
LIMIT AND F(3) ARE SAME.AND FUNCTION BECOMES
CONTINUOUS AT 3.SO THIS IS CALLED REMOVABLE DIS-
CONTINUITY.
NON-REMOVABLE DISCONTINUITY
If left hand limit , right hand limit at point say, 'a' and f(a)
are different; then this is non- removable discontinuity.
we cannot make this function continuous by redefining f(a)
EX:
F(X)=2 , X<10
=3 , X=10
=5 , X>10
IN THIS EXAMPLE;
Lim F(x)=2
x->10-
Lim F(x)=5
x->10+
and F(10)=3.
as 2≠3≠5
then function is not continuous
this is called as non removable discontinuity.
we cannot fix a single value of F(10) as there are different values of
left hand limit and right hand limit.(2 and 5).
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